When 80.0 mL of a 0.812 M barium chloride solution is combined with 40 mL of a 1.52 M potassium sulfate solution, 10.8 g of barium sulfate precipitates. What is the % yield of this reaction

76.1%

Explanation:

The reaction that takes place is:

First we determine how many moles of each reactant were added:

Thus K₂SO₄ is the limiting reactant.

Using the moles of the limiting reactant we calculate how many moles of BaSO₄ would have been produced if the % yield was 100%:

Then we convert that theoretical amount into grams, using the molar mass of BaSO₄:

Finally we calculate the % yield:

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