Describe the preparation
of 2.00h of o.108m Bach
from Bad. 28 (244-3 g/mal)

The question is incomplete, the complete question is; Describe the preparation of 2.00 L of 0.108 M BaCl2 from BaCl2.2H2O

See explanation

Explanation:

First we must know the molar mass of the compound = 244.3 g/mol

Now we must calculate the number of moles of BaCl2.2H2O in the solution.

number of moles = concentration * volume = 0.108 M * 2.00 L = 0.216 moles

Now the mass of solid that we need to take can be obtained from;

number of moles = mass/molar mass

mass = number of moles * molar mass

mass = 0.216 moles * 244.3 g/mol

Mass = 52.8 g

Hence, we must weigh 52.8 g of BaCl2.2H2O accurately in a balance and dissolve it in 2 L of water to give 0.108 M solution of BaCl2.2H2O.

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.