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Chemistry, 22.06.2019 14:30, joejoefofana
Consider the reduction reactions and their equilibrium constants. cu+(aq)+eโโฝโโโcu(s)pb2+(aq)+2eโโฝโโโ pb(s)fe3+(aq)+3eโโฝโโโfe(=6.2ร108=4. 0ร10โ5=9.3ร10โ3 cu + ( aq ) + e โ โฝ โ โ โ cu ( s ) k =6.2ร 10 8 pb 2 + ( aq ) +2 e โ โฝ โ โ โ pb ( s ) k =4.0ร 10 โ 5 fe 3 + ( aq ) +3 e โ โฝ โ โ โ fe ( s ) k =9.3ร 10 โ 3 arrange these ions from strongest to weakest oxidizing agent.
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