Please answer Question 3 (4 points)
If an unknown substance has a specific heat of 0.246J/gxC, is cooled by 15.5 degrees C and releases 700.0 J of enegy, what is the mass of that
sample?

183.6kg

Explanation:

Given parameters:

Specific heat of the substance  = 0.246J/g°C

Change in temperature  = 15.5°C

Amount of energy released  = 700J

Unknown:

Mass of the sample  = ?

Solution:

To solve this problem we used the energy equation:

        H  = m c Δt

 H is the energy released

  m is the unknown mass

  c is the specific heat

 Δt  is the change in temperature

Now insert the parameters and find m;

 700  = m x 0.246 x 15.5

  700 = 3.8m

     m  = 183.6kg