Chemistry, 05.02.2020 07:56, rhiannpelham60
Ammonia is an important ingredient in many fertilizers. the main process by which ammonia is made is the haber process. in this process, nitrogen gas and hydrogen gas are reacted to form ammonia at high temperatures. this sentence most likely explains why this reaction is carried out at high temperature.
a.) ammonia is unstable at room temperature.
b.) high temperatures increase the activation energy of the reaction.
c.) high temperatures make the gas molecules move more quickly.
d.) the reaction becomes exothermic at high temperatures.
Answers: 3
Chemistry, 22.06.2019 01:30, adrian08022
When an object falls through the air and encounters air resistance its overall speed will be than if it had not encountered air resistance? (one word answer)
Answers: 2
Chemistry, 22.06.2019 02:50, JuniperGalaxy
Consider the equilibrium system: 2icl(s) ⇄ i2(s) + cl2(g) which of the following changes will increase the total amount of of cl2 that can be produced? all of the listed answers are correct decreasing the volume of the container removing the cl2 as it is formed adding more icl(s) removing some of the i2(s)
Answers: 1
Chemistry, 22.06.2019 16:00, winnie45
He table below gives the atomic mass and relative abundance values for the three isotopes of element m. relative abundance (%) atomic mass (amu) 78.99 23.9850 10.00 24.9858 11.01 25.9826 what is the average atomic mass (in amu) of element m? 2.86 5.36 24.30 24.98
Answers: 2
Chemistry, 22.06.2019 21:50, BookandScienceNerd
Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes
Answers: 1
Ammonia is an important ingredient in many fertilizers. the main process by which ammonia is made is...
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