A solid rocket booster is ordered with the specification that it is to produce a total of 10 million pounds of thrust. If this number is mistaken for the thrust in Newtons, by how much, in pounds, will the thrust be in error?

- 7751798.6 pounds = - 7751 × 10^3 pounds.

Explanation:

Without mincing words, let us dive straight into the the solution to the above problem.

So, we are given the following data oe parameters which is going to help in solving this particular Question or problem.

We are given that the number of thrust = 10 million pounds of thrust. This is also equal to mistaken thrust which is = 10 million Newtons.

Thus, if 4.448 newton = 1 ponds, then,

10 million Newtons = x pounds. Hence,

x = 10 million Newtons/ 4.448 Newtons = 2248201.4 pounds.

Hence, 10 million Newtons = 2248201.4 pounds.

Therefore, error = mistaken thrust( in pounds) - total thrust(in pounds) = 2248201.4 pounds - 10 million thrust = - 7751798.6 pounds.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

idk what is it? is this a question that you know the answer or u dont