Select all the correct answers. In this reaction, how does the rate of forward reaction vary with the concentration of the product?
2H, S() =2H() + S(g)
O It increases with an increase in the concentration of S-(g).
OIt decreases with a decrease in the concentration of H().
OIt increases with a decrease in the concentration of H-(g).
It decreases with an increase in the concentration of S,().
It decreases with increase in the concentration of Ha().

The correct answers :

It increases with a decrease in the concentration of H₂(g).

It decreases with an increase in the concentration of S₂(g).

It decreases with an increase in the concentration of H₂(g).

Forward reaction : rate to form product

In equilibrium :

The product decreases ⇒ system will move from left to right(forward reaction)

The product increases ⇒ system will move from right to left(reverse reaction)

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.