5) Determine the mass if lithium hydroxide that is produced when 12.87 g of lithium nitride reacts with an excess of water according to the following process.
Li:N + 3 H2O → 3 LiOH + NH3

26.54 grams

Explanation:

To calculate the moles :

is the limiting reagent as it limits the formation of product and is the excess reagent

According to stoichiometry :

As 1 moles of give = 3 moles of

Thus 0.369 moles of give =  of

Mass of

Thus  26.54 g of will be produced from the given mass.