The volume of a container of gas is 2.65 L and is at a temperature of 22.4°C. What is the new volume if the temperature is increased to 99.6 °C?
A) 11.8L
B) 3.34 L
C) 0.596 L
D) 10.6L

B) 3.34

Explanation:

V1/T1 = V2/T2

So V2= (T2xV1)/T1

Side note Temp for using gas law is always kelvin (Celsius +273.15)

Volume is always in Liters

So V2 = (372.6Kx2.65L)/295.55L

Which results in 3.34L

sup bro, im dumb, but this is what i found xd

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