A sample of a gas occupies a volume of 35.0 L at 25°C and 4.50 atm. What is the volume occupied by this gas at 20°C and 5.60 atm?

The final volume, occupied by the gas at 20° C (293.15 K) and 5.60 atm, is approximately 27.65 L

Explanation:

The given parameters are;

The initial volume, V₁ = 35.0 L

The initial temperature, T₁ = 25 °C = 298.15 K

The initial pressure, P₁ = 4.50 atm

The final volume, V₂ = Required

The final temperature, T₂ = 20 °C = 293.15 K

The final pressure, P₂ = 5.60 atm

From the combined gas equation, we have;

P₁·V₁/T₁ = P₂·V₂/T₂

∴ V₂ = (P₁·V₁/T₁) × T₂/P₂

By substituting the known values, we get;

V₂ = (4.50 × 35.0/298.15) × 293.15/5.60 ≈ 27.65

Therefore, the final volume, occupied by the gas at 20° C (293.15 K) and 5.60 atm, V₂ ≈ 27.65 L

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