For the reaction: 4Fe+3O2= 2Fe2O3 if 100g of Fe are used how much of O2 is used

Mass = 42.88 g

Explanation:

Given data:

Mass of iron = 100 g

Mass of O₂ = ?

Solution:

Chemical equation:

4Fe + 3O₂       →    2Fe₂O₃

Number of moles of Iron:

Number of moles = mass/molar mass

Number of moles = 100 g/ 55.85 g/mol

Number of moles = 1.79 mol

Now we will compare the  moles iron with oxygen.

                               Fe          :              O₂

                                 4            :               3

                                 1.79        :           3/4×1.79 = 1.34 mol

Mass of oxygen used:

Mass = number of moles × molar mass

Mass = 1.34 mol × 32 g/mol

Mass = 42.88 g

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