How many moles of hydrochloric acid are present in 62.2 mL of 4.54 M HCl solution

Moles of HCl = 0.282

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

Where

M = Molarity

n = number of moles of solute

V = Volume of solution

The volume of HCl=62.2 ml=0.0622 L

The molarity of HCl = 4.54 M

Then moles of HCl :

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