If the density of a liquid 102g/cm^3, how many milligrams will be in 63 mL of that liquid?

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

63 mL = 63 cm³

We have

mass = 102 × 63 = 6426

But 1 g = 1000 mg

6426 g = 6426000 mg

We have the final answer as

Hope this helps you

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2