The electron configuration of an element is 1s22s22p6. Describe what most likely happens when an atom of this element comes near an atom having seven valence electrons. Please help!!!

The element with an electron configuration of 1s2 2s2 2p6, has a full outer shell of electrons, 2 electrons in the 2s sub-shell and 6 electrons in the 2p sub-shell which gives a total of 8 valence electrons. Therefore, this atom is already stable and does not need to form a bond in order to complete its octet. Atoms of elements that already have a full outer shell of electrons are termed noble gases. Noble gases are chemically inert, so when this element approaches an atom with seven valence electron no reaction will occur

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

fe 55.85 g/mol and h2o 18.02 g/mol.