Calculate Ecell for the reaction below 2AgBr(aq) + 2Hg(l) --> 2Ag(s) + Hg2Br2(s)

given the following standard reduction potentials

Hg2Br2(s) + 2e- --> 2Hg(l) + 2Br-(aq) E = +0.140 V

AgBr(aq) + e- --> Ag(s) + Br-(aq) E = +0.071 V

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

can you attach the

it would be a gas formation