How much heat is necessary to vaporize 685 g of H20 at 100°C? The heat of vaporization of H2O is 540 cal/g.
0 370,000 cal
O 1.22 x 103 cal
O 88,400 cal
01.27 kcal
h
Question 8
3.33 pts

370,000 cal

Explanation:

Step 1: Given data

Step 2: Calculate the heat necessary to vaporize 685 g of water

Vaporization is the process in which a liquid converts to a gas, at a constant temperature. The heat required (Q) is:

Q = ΔH°vap × m

Q = 540 cal/g × 685 g

Q = 3.70 × 10⁵ cal

smooth muscle is composed of involuntary muscles found within the walls of organs and structures such as the esophagus, stomach, intestines, and blood vessels. those muscles push materials like food or blood through organs. unlike skeletal muscle, smooth muscle can never be under your control.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally