What is the percent yield of titanium (IV) oxide, if 10.2 g are formed when 25.7 g of titanium (IV) chloride react?
TiCl4 (s) + O2 (g) - TiO2 (s) + 2 Cl2 (g)

Percent yield = 91%

Explanation:

Given data:

Percent yield of TiO₂ = ?

Actual yield = 10.2 g

Mass of TiCl₄ react = 25.7 g

Solution:

Chemical equation:

TiCl₄  + O₂   →    TiO₂  + 2Cl₂

Number of moles of TiCl₄:

Number of moles = mass/molar mass

Number of moles = 25.7 g/ 189.7 g/mol

Number of moles = 0.14 mol

Now we will compare the moles of  TiCl₄  and TiO₂.

                       TiCl₄           :            TiO₂

                         1                :              1

                         0.14           :              0.14

Theoretical yield:

Mass = number of moles ×molar mass

Mass = 0.14 mol × 79.86 g/mol

Mass = 11.2 g

Percent yield:

Percent yield = [actual yield / theoretical yield ]  × 100

Percent yield = [10.2 g / 11.2 g ]× 100

Percent yield = 91%

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.

they are both synthetic elements

explanation:

d