How many moles are present in 1.2L of a 0.1 M NaCl solution?

0.12 mole.

Explanation:

From the question given above, the following data were obtained:

Molarity of NaCl solution = 0.1 M

Volume of NaCl solution = 1.2 L

Mole of NaCl =.?

Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

Thus, we can obtain the mole of NaCl in the solution by using the above formula as follow:

Molarity of NaCl solution = 0.1 M

Volume of NaCl solution = 1.2 L

Mole of NaCl =.?

Molarity = mole /Volume

0.1 = mole of NaCl /1.2

Cross multiply

Mole of NaCl = 0.1 × 1.2

Mole of NaCl = 0.12 mole

Therefore, 0.12 mole of NaCl is present in the solution.

answer; i believe that the correct answer is (a) potassium(k)