The ΔHvap of a certain compound is 47.45 kJ·mol−1 and its ΔSvap is 59.15 J·mol−1·K−1. What is the boiling point of this compound?

802.2 K

Explanation:

To solve this problem we can use the formula:

Where Tb is the boiling point (in K).

We already know the values of both ΔHvap and ΔSvap, so we calculate Tb:

Tb = 47.45x10³J·mol⁻¹/59.15 J·mol⁻¹·K⁻¹

So the boiling point of the compound is 802.2 K (or 529 °C)

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