. Write a balanced equation for the combustion of propane,
C3H8
When balanced, the equation indicates
that moles of
O2 are required for each mole of C3Hg8

C3H8 + 5O2 = 3CO2 + 4H2O

Explanation:

1.  First start by writing out the unbalanced equation

2.  Count all the atoms on both sides of the equation

C = 3         C =1

H = 8         O=3

O = 2         H =1

3.   Start by balancing the carbon atoms. What would it take to have 3 Carbon atoms on the left? You would add a 3 in front of the carbon atoms on the left side to match the carbon atoms on the right.

4.   Now Try balancing the H atoms. You have 8 H atoms on the right and 1 H atom on the left. To balance these out you would need to add a 4 in front of the H atom which gives you 8 on both sides.

5.  Now balance out the oxygen atoms. Since we added coefficients to the compounds on the left we now have 10 oxygen on the left 4x1=4 + 3x2=6 now balance out the right side of the equation by adding a 5 in front of the O2 5x2 Oxygen gives you 10.

I hope this helps

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.

b.false that your answer