PLEASE HELP If 9.30 g of potassium reacts with 2.50 g of O2 to form K2O , what is the limiting reagent and what is the theoretical yield of the reaction?

Hint: write the balanced reaction

K - 39.10 g/mol

O - 15.999 g/mol

ANSWER CHOICES:

A.) O2 is limiting, 11.2 g of K2O formed

B.) K is limiting, 14.7 g of K2O formed

C.) K is limiting, 11.2 g of K2O formed

D.) O2 is limiting, 14.7 g of K2O formed

E.) O2 is limiting, 19.2 g of K2O formed

C.) K is limiting, 11.2 g of formed

Explanation:

To calculate the number of moles, we use the equation:

Putting in the values we get:

According to stoichiometry :

4 moles of require 1 mole of

Thus 0.238 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 4 moles of give = 2 moles of

Thus 0.238  moles of will give =  of

Mass of

Thus K is limiting and 11.2 g of will be formed.

1 is the answer to this problem