Help me please .

Hey, you have to solve it by Stichiometryanswer is option A I have explained every option for your understanding.

Explanation:

(a.)**For option A, the volume of CO2 produced at STP will be 5.6 not 30.8 by solving equation for part I

By Stichiometry,

moles of CO2, n=11.2/22.4 = 0.5

Volume of CO2, V=11.2×0.5 =5.6

(b.)**For option B, the statement is correct

n(moles) of O2 =32/32 = 1 mol

we have to use stichiometry to find moles of CO2

n= 1/2 × 1 (coefficient of CO2/coefficient of O2) × mol of O2 (coz O2 is limiting reagent in 2nd option)

n= 0.5 mol

Mass= n × Molecular Mass

Mass= 0.5 × 44

Mass= 22g

(c.)**option C, is correct acc. to statement

(d.)**option D, is correct acc. to statement

(e.)**option E, is correct acc. to statement

Answer to this question is A part.

Hope it helps

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

the product of the pressure and volume is also constant