What is the mass of element P which reacts with 1 .62g of element Q to form a compound with formula Q2p3 (relative atomic mass p,16;Q,27)

Mass of element P = 1.44 g

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison

MW Q₂P₃ = 2.27 + 3.16=102 g/mol

Mass Q₂P₃ (MW=102 g/mol) :

Mass P (Ar=16) :

or you can solve it with mol :

Reaction

3P + 2Q ⇒ Q₂P₃

mol Q :

mol P :

mass P :

m=9

step-by-step explanation: