Demonstrate how you can prepare 250ml 0.25M hydrogen peroxide from a solution of 20g/100ml of hydrogen peroxide.

Determine the volume of the initial solution,  

V

1

, to produce the required solution. We do this by applying the dilution equation,

M

1

V

1

=

M

2

V

2

where M is the concentration and V is the volume, while the subscripts respectively depicts the initial and required solutions. Now, we must express the concentration of the initial solution in terms of moles per liter, wherein we use the conversion factors such as the molar mass, 34.015 g/mol, and 1000 mL/L. We proceed converting the concentration.

M

1

=

20

g

1000

m

L

÷

34.015

g

/

m

o

l

×

1000

m

L

/

L

≈

5.88

M

Now, we are given the following values:

M

2

=

0.25

M

V

2

=

250

m

L

We proceed with the solution by applying the dilution equation and then plugging in the given values.

M

1

V

1

=

M

2

V

2

V

1

=

M

2

V

2

M

1

V

1

=

(

0.25

M

)

(

250

m

L

)

5.88

M

V

1

≈

11

m

L

Therefore, we need to take  

11

m

L

of the initial solution and dilute it to the desired volume to produce the required solution.

that's the explanation but, this helps if ur in higher classes though :>

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.