What is the amount of heat absorbed when the temperature of 75 grams of water increases from 20 to 75

17242,5J

Explanation:

Given parameters:

Mass of water  = 75g

Initial temperature  = 20°C

Final temperature  = 75°C

Unknown:

Amount of heat absorbed  = ?

Solution

To find the amount of heat absorbed by water;

      H  = mcΔt

 m is the mass

  c is the specific heat capacity of water  = 4.18J/g°C

 Insert the parameters and solve;

       H  = 75 x 4.18 x (75 - 20)

       H  = 17242,5J

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