Calculate the lithium ion (Li+) concentration for a 0.821 M Li2S solution.

The lithium ion[Li⁺]=1.642 M

Ionic compounds will dissociate into ions when dissolved in water. The strength of the dissociation depends on the strength of the electrolyte properties. The stronger it is, the more ions will dissociate

Reaction

Li₂S⇒2Li⁺+S²⁻

mol ratio Li₂S : Li⁺: S²⁻ = 1 : 2 : 1

so the lithium-ion (Li⁺) concentration :

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

answeridentity;