If I place a balloon in my fridge that initially has a pressure of 1.02 atm and a temperature of 11.2 °C, what will be the pressure (in atm) of the balloon when it is
fully cooled to 4.00°C by my refrigerator?

P₂ = 0.99 atm

Explanation:

Given data:

Initial pressure = 1.02 atm

Initial temperature = 11.2°C

Final pressure = ?

Final temperature = 4.00°C

Solution:

Initial temperature = 11.2°C (11.2+273 = 284.2 K)

Final temperature = 4.00°C (4.00+273 = 277 K)

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1.02 atm / 284.2 K = P₂/277 K

P₂ = 1.02 atm × 277 K / 284.2 K

P₂ = 282.54 atm. K /293 K

P₂ = 0.99 atm

answer; /// i do believe that the correct answer is (c)nuclear bond

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )