5. You add 11.00 mL of 0.800 M NaOH to 50.00 mL of pure water, and to this mixture you then add 3.00 mL of 0.200 M HCl. What will be the pH of the resulting solution

pH = 13.11

Explanation:

NaOH reacts with HCl to produce H2O and NaCl. pH depends of this reaction. The reactant in excess determine the pH of the solution:

NaOH + HCl → H2O + NaCl

1 mole of NaOH reacts with 1 mole of HCl

To determine limiting reactant we need to find moles of each reactant:

Moles NaOH:

0.011L * (0.800 mol / L) = 0.0088 moles NaOH

Moles HCl:

0.003L* (0.200mol / L) = 0.0006 moles HCl

That means limitng reactant is HCl and moles in excess of NaOH are:

0.0088moles NaOH - 0.0006 moles = 0.0082 moles NaOH =

0.0082 moles OH⁻

In 11.00mL + 50.00mL + 3.00mL = 64.00mL = 0.06400L

[OH-] = 0.0082 moles OH- / 0.064L = 0.1281M OH-

pOH = -log [OH-] = 0.89

pH = 14 - pOH

hurricanes form when warm, moist air from the ocean surface quickly rises into the atmosphere and forms storm clouds and rain. when the clouds are formed, heat is released which warms the cool air in the upper regions of the atmosphere so that the cycle can continue. which two phases of the water cycle are repeated in this process?