When heated, calcium carbonate decomposes according to the equation given below: CaCO3 --> CaO + CO2
If 3.0 moles of CaCO3 are decomposed, how many grams of CO2 will be produced?

44.0 g
88.0 g
132 g
3.00 g

132g

Explanation:

The reaction equation is given as:

          CaCO₃  →  CaO  + CO₂

Given;

 Number of moles of CaCO₃  = 3 moles

Unknown:

Mass of CO₂ produced  = ?

Solution:

From the balanced reaction equation;

          1 mole of CaCO₃ will produce 1 mole of CO₂;

         3 mole of CaCO₃ will then produce 3 moles of CO₂

To find the mass of CO₂;

  Mass of CO₂ = number of moles x molar mass

      Molar mass of CO₂  = 12 + 2(16) = 44g/mol

 Mass of CO₂ = 3 x 44  = 132g