0.075 grams of condensed vapor is present when a student uses the Dumas method. The
experiment was conducted at 70°C, 1 atm and
the volume of the container is 0.045 L. What is
the molar mass of the material?

The molar mass of the material has been 46.93 grams.

The gas been assumed to be an ideal gas. For an ideal gas:

Pressure × Volume = moles × R constant × Temperature.

Moles can be given as:

Moles =

Ideal gas equation can be given in terms of moles as:

Pressure × Volume = × R constant × Temperature.

Pressure = 1 atm

Volume = 0.045 L

Weight = 0.075 grams

R = 0.08206 L.atm/mol.K

Temperature = 70 = 343.15 K

Substituting the values:

1 × 0.045 = × 0.08206 × 343.15

0.045 = × 28.1588

Molecular weight = 46.93 grams.

The molar mass of the material has been 46.93 grams.

For more information about the molar mass, refer to the link:

link

The molar mass of the material : 47 g/mol

In general, the gas equation can be written

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K

T = temperature, Kelvin

1 a

2 d

3 a

4 c

explanation: