The following sequence of reactions occurs in the commercial productions of aqueous nitric acid: 4NH3(g) + 5O2(g) ⟶ 4NO(g) + 6H2O(l); LaTeX: ΔH = -907 kJ

2NO(g) + O2(g) ⟶ 2NO2(g); ΔH = -113 kJ

3NO2 + H2O(l) ⟶ 2HNO3(aq) + NO(g); ΔH = -139 kJ

Determine the total energy change for the production of one mole of aqueous nitric acid by this process.

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answer carbon and three oxygen atoms;

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.