Calculate the molarity of 32.9 g32.9 g of MgS MgS in 971 mL 971 mL of solution.

0.60 M

Explanation:

Given data:

Mass of MgS = 32.9 g

Volume of solution = 971 mL (0.971 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of MgS:

Number of moles = mass/molar mass

Number of moles = 32.9 g/ 56.38 g/mol

Number of moles = 0.58 mol

Molarity of solution:

M = 0.58 mol/ 0.971L

M = 0.60 M

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