How many mL of 0.650 M solution can be prepared by dissolving 15.0 g of copper(II) nitrate in water?

123.1L

Explanation:

Given parameters:

Molarity of Cu(NO₃)₂  = 0.650M

Mass of  Cu(NO₃)₂ = 15g

Unknown:

Volume of  Cu(NO₃)₂ = ?

Solution:

To solve this problem, we have to first find the number of moles of the given mass;

  Number of moles of Cu(NO₃)₂  =

   Molar mass of Cu(NO₃)₂  = 63.5 + 2 (14 + 3(16)) = 187.5g/mol

 Number of moles of Cu(NO₃)₂  =  = 0.08 mol

Molarity is given as;

  Molarity  =  

         Volume  =  

  Insert the parameters and solve;

        Volume  =  = 0.12L

Now mL;

         1L  = 1000mL

        0.12L will give 1000 x 0.12  = 123.1L

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