What is the volume of 902.0 g of C₂H₄ gas at STP

Volume  = 722.1 L

Explanation:

Given data:

Mass of gas = 902.0 g

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Volume of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will calculate the number of moles of C₂H₄.

Number of moles = mass/molar mass

Number of moles = 902.0 g/ 28.05 g/mol

Number of moles = 32.2 mol

Volume of gas:

PV = nRT

1 atm ×V = 32.2 mol × 0.0821   atm.L/ mol.K  × 273.15 K

V = 722.1 atm.L/1 atm

V = 722.1 L

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.