K₂O +2Li Li₂O +2k how do you solve?

K₂O +2Li --> Li₂O +2K

Explanation:

On the left side, K has 2 atoms and O has one combines with Li having 2 atoms. When the process starts Li burns and got atoms from O.

Hence O has 2 ions and Li has 1 ion

so to complete the bond, Two Li will have 2 ions which can complete O by sharing his 2 icons. i.e. Li₂O

and Two atoms of K can exist like 2K

So the equation will be like

K₂O +2Li --> Li₂O +2K

-be a crystalline solid

- be soluble in water

-conduct electricity

hope this : )

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g