How many grams of H2SO4 are needed to react with 78.86 grams of AI(NO3)3 ?
I

53.18 grams of H₂SO₄ are needed to react with 78.86 grams of Al(NO₃)₃.

Explanation:

The balanced reaction between Al(NO₃)₃ and H₂SO₄ is:

2 Al(NO₃)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 HNO₃

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents are required:

Being the molar mass of the elements:

then the molar mass of the reactants are:

Then, by reaction stoichiometry, the following reagent mass amounts are required:

Then you can apply the following rule of three:  If by stoichiometry 436 g of Al(NO₃)₃ react with 294 g of H₂SO₄, 78.86 g of Al(NO₃)₃ with how much mass of H₂SO₄ will it react?

mass of H₂SO₄=53.18 g

53.18 grams of H₂SO₄ are needed to react with 78.86 grams of Al(NO₃)₃.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)