Why did a portion of the tabletop get cold when natasha placed her cold drink on the table.

a. the table's molecules were vibrating more slowly in that area.
b. the tables molecules had spread further apart in that area
c. the tables molecules had gained energy in that area
d. the tables molecules had become free of each other in that area

Option (A) is the correct answer.

Explanation:

When two objects are placed in contact with each other then the heat will flow from an object with high temperature to low temperature until the temperature of both the objects become equal.

So, when a cold drink is placed on the table then heat from the table gets transferred to the cold drink.

During this transfer temperature of table will decrease due to which kinetic energy of its molecules will also decrease.

As a result, the molecules of table around that area will vibrate more slowly.

Thus, we can conclude that a portion of the tabletop get cold when Natasha placed her cold drink on the table because the table's molecules were vibrating more slowly in that area.

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%