A 200.0-mL sample of helium gas is in a cylinder with a movable piston at 110 kPa and 275 K. The piston is pushed in until the sample has a volume of 95.0 mL. The new temperature of the gas is 310. K. What is the new pressure of the sample? a)51.1 kPa b)261 kPa c)249 kPa d)274 kPa

Option B. 261 KPa.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 200 mL

Initial pressure (P1) = 110 kPa

Initial temperature (T1) = 275 K.

Final volume (V2) = 95 mL

Final temperature (T2) = 310 K

Final pressure (P2) =?

The new pressure (P2) can be obtained by using the following formula as illustrated below:

P1V1 /T1 = P2V2 /T2

110 × 200/275 = P2 × 95/310

22000 / 275 = P2 × 95/310

80 = P2 × 95/310

Cross multiply

80 × 310 = P2 × 95

24800 = P2 × 95

Divide both side by 95

P2 = 24800/95

P2 = 261 KPa.

Thus, the new pressure of the gas is 261 KPa.

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