2. How many atoms of zinc are present in 0.48 mol of zinc?
(show solution)

Explanation:

The number of atoms of zinc can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.48 × 6.02 × 10²³

We have the final answer as

Hope this helps you

2.89× 10²³ atom

Explanation:

Given data:

Number of atoms of Zn = ?

Number of moles of Zn = 0.48 mol

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole = 6.022 × 10²³ atom

0.48 mol ×  6.022 × 10²³ atom / 1mol

2.89× 10²³ atom

the answer would be a

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.