If the pressure exerted by a gas at 25 degrees C in a volume of 0.044 L is 3.81 atm, how many moles of gas are present?

The moles of gas has a pressure of 3.81 atm and volume 0.044 L has been 6.85 mmol.

The gas has been exhibiting the ideal nature. According to the ideal gas equation:

PV =nRT

P = pressure = 3.81 atm

V = volume = 0.044 L

R = constant = 0.0821

T = temperature = 25 = 298 K

Substituting the value:

3.81 0.044 = n  0.0821  298

0.16764 = 24.4658 n

n = 0.00685 mol

n = 6.85 mmol

The moles of gas has a pressure of 3.81 atm and volume 0.044 L has been 6.85 mmol.

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0.0069 mol

Explanation:

Given data:

Temperature = 25°C

Volume of gas = 0.044 L

Pressure of gas = 3.81 atm

Number of moles of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273 = 298 K

3.81 atm × 0.044 L = n × 0.0821 atm.L/ mol.K  ×  298 K

0.17  atm.L = n ×24.47 atm.L/ mol

n = 0.17  atm.L/24.47 atm.L/ mol

n = 0.0069 mol