How much energy in Joules, does 80 (g) grams of water at an initial temperature of 40°C need to absorb to have its temperature raised to a final. temperature of 60 °C

Q = 6688 J

Explanation:

Given data:

Energy absorbed = ?

Mass of water = 80 g

Initial temperature = 40°C

Final temperature = 60°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

specific heat capacity of water 4.18 j/g.°C

ΔT = 60°C -  40°C

ΔT = 20°C

Q = 80 g ×4.18 j/g.°C ×  20°C

Q = 6688 J

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