What is the balanced chemical equation for the reaction of solid calcium metal and aqueous aluminum nitrate?

3 Ca(s) + 2 Al(NO₃)₃(aq) ⇒ 3 Ca(NO₃)₂(aq) + 2 Al(s)

Explanation:

Let's consider the single displacement reaction between solid calcium metal and aqueous aluminum nitrate. The unbalanced chemical equation is:

Ca(s) + Al(NO₃)₃(aq) ⇒ Ca(NO₃)₂(aq) + Al(s)

We have 3 nitrates on the left and 2 nitrates on the right, so we will multiply Al(NO₃)₃(aq) and Ca(NO₃)₂(aq) by 2 and 3, respectively, to balance them.

Ca(s) + 2 Al(NO₃)₃(aq) ⇒ 3 Ca(NO₃)₂(aq) + Al(s)

Finally, we have to add coefficients before Ca(s) and Al(s) to balance the equation.

3 Ca(s) + 2 Al(NO₃)₃(aq) ⇒ 3 Ca(NO₃)₂(aq) + 2 Al(s)

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml