A balloon contains 3300 mL of helium gas at 63 °C. What is the final volume, in milliliters, of the gas when the temperature changes to each of the following, if pressure and amount of gas do not change? Part A 78 C Express your answer to two significant figures and include the appropriate units. UA Vi= Value Units

The final volume : 3.4 L

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

V₁=3300 ml

T₁=63 + 273=336 K

T₂=78+273=351 K

the final volume :

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

narendra modi is currently the pm of india

explanation: