A cylinder fitted with a piston has 10 dm3 of a gas 27ºC. How can you double the pressure
by varying only the volume?

need help asap

when the pressure of gas is decreased, the volume increases. this relationship between pressure and volume is called Boyle's law. So, at constant temperature, the answer to your answer is: the volume decreases in the same ratio as the ratio of pressure increases.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.