If 2.50g of CuSO4 is dissolved in 8.95 x 10^2 mL of 0.300 M NH3, calculate the concentrations of the following species at equilibrium: Cu^2+, NH3, Cu(NH3)4^2.
I tried to solve and came up with the following-
Cu^2+ = 1.1149x10^-13 (Which was all wrong except for the 10^-13)
NH3 = .230 (Which was correct)
Cu(NH3)4^2+ = 0.069720 (Which was wrong)
Can someone please show me where I am going wrong.
Answers: 3
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If 2.50g of CuSO4 is dissolved in 8.95 x 10^2 mL of 0.300 M NH3, calculate the concentrations of the...
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