A solution is made by adding 5.01 g of iron sulfate to 75.3 g of water. What is the mass percentage of iron sulfate in this solution?

6.24 % of FeSO₄

Explanation:

Solute mass: 5.01 g of FeSO₄

Solvent mass: 75.3 g of water

Solution mass = solute mass + solvent mass

5.01 g + 75.3 g = 80.31 g

We can apply a rule of three. Mass percentage means the mass of solute which is contained in 100 g of solution. Then,

In 80.31 g of solution we have 5.01 g of solute

In 100 g solution, we may have (5.01  . 100)/ 80.31 = 6.24 g of solute.

This is the mass percentage: 6.24%

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