Sealed containers of fizzy drinks contain dissolved carbon dioxide. The dissolved CO2 is in equilibrium with a small quantity of gaseous CO2 at the top of the container. Find partial pressure of CO2 gas in 355 ml can of fizzy drink at 25C if the concentration of CO2 in the fizzy drink 0.1 M. Given that Henry’s law constant for CO2 is 3.3 x 10-2 M atm-1.

What mass of CO2 is dissolved in a 355 ml can of fizzy drink when it is stored at 25C.

3 atm

1.6 g

Explanation:

Step 1: Given data

Step 2: Find partial pressure (P) of CO₂ gas

We will use Henry's law.

C = k × P

P = C / k

P = 0.1 M / 3.3 × 10⁻² M atm⁻¹

P = 3 atm

Step 3: Calculate the mass of CO₂ gas

The molar mass of carbon dioxide is 44.01 g/mol.

0.355 L × 0.1 mol/L × 44.01 g/mol = 1.6 g

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3