I need a graph and at least a 350-word essay I'll be giving a brainlist to gives
This is due: at 5:45 PM

Make a graph of the data collected.
Label the x-axis as time.
Label the y-axis as the number of undecayed atoms.
Be sure to title the graph.
Turn the graph into your teacher.
Write a summary paragraph discussing this experiment and the results. Use the following questions to help guide the content of your paragraph.
What was your hypothesis? According to your data, do you think your hypothesis was correct?
What is a half-life?
When does a radioactive sample emit the largest number of decay particles? Why is this information important? (How can it be applied in our world today?)
Do you think the shape of the curve on your graph would change if you increased the half-life to 20 seconds? What does this reveal about radioactive decay?
Do you think the shape of the curve on your graph would change if you started with a smaller sample, say 50 atoms (pennies)? What does this reveal about radioactive decay?

Well technically there are two correct answers b and d. but for you its probably b in general.good day sir/ma'am : ) (i know not gender)

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

The answer to your q the total mass is 73

The answer is the third choice