For the reaction of nitric oxide and oxygen to form nitrogen dioxide, the reaction begins with 12.0 g of nitric oxide and 12.0 g of oxygen at 25oC in a 10.0 L container. At equilibrium, the pressure in the container is 1148 mmHg, what is Kp?

Explanation:

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In this case, since the undergoing chemical reaction is:

The equilibrium expression in terms of pressures is:

Thus, for the initial conditions, we compute the initial pressures of both nitric oxide and oxygen:

Next, since the equilibrium pressure is 1148 mmHg or 1.51 atm, we can write:

Thus, the Kp turns out:

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explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.