Fluorine (F) and bromine (Br) are in the same group on the periodic table. How do atoms of these elements compare when they form bonds? Both a fluorine atom and a bromine atom lose one electron, and both atoms become stable.
A fluorine atom becomes stable by losing one electron, but a bromine atom cannot become stable by losing only one electron.
Both a fluorine atom and a bromine atom gain one electron, and both atoms become stable.
A fluorine atom becomes stable by gaining one electron, but a bromine atom cannot become stable by gaining only one electron.

Both a fluorine atom and a bromine atom gain one electron, and both atoms become stable.

Explanation:

The two elements compare when they form bonds in that when both a fluorine atom and a bromine atom gain one electron, they both become stable.

it is a good conductor

explanation:

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole